By Mahima Ranjan Adhikari, Avishek Adhikari

ISBN-10: 8132215982

ISBN-13: 9788132215981

ISBN-10: 8132215990

ISBN-13: 9788132215998

The ebook is essentially meant as a textbook on sleek algebra for undergraduate arithmetic scholars. it's also valuable should you have an interest in supplementary examining at a better point. The textual content is designed in any such manner that it encourages autonomous pondering and motivates scholars in the direction of extra learn. The publication covers all significant issues in staff, ring, vector house and module concept which are often contained in a customary glossy algebra textual content.

In addition, it stories semigroup, team motion, Hopf's workforce, topological teams and Lie teams with their activities, functions of ring idea to algebraic geometry, and defines Zariski topology, in addition to purposes of module concept to constitution conception of earrings and homological algebra. Algebraic facets of classical quantity idea and algebraic quantity concept also are mentioned with an eye fixed to constructing sleek cryptography. themes on functions to algebraic topology, class thought, algebraic geometry, algebraic quantity thought, cryptography and theoretical computing device technology interlink the topic with various components. each one bankruptcy discusses person issues, ranging from the fundamentals, with assistance from illustrative examples. This accomplished textual content with a large number of techniques, purposes, examples, workouts and ancient notes represents a necessary and particular resource.

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**Example text**

6 (Schroeder–Bernstein Theorem) If for given two sets X and Y , X ∼ Y1 ⊂ Y and Y ∼ X1 ⊂ X, then X ∼ Y . Proof Let f : X → Y1 be a bijection and f (X1 ) = Y2 . Then X1 ∼ Y2 and Y1 ⊃ Y2 . Now Y ⊃ Y1 ⊃ Y2 . Moreover, Y ∼ X1 (by hypothesis) and X1 ∼ Y2 ⇒ Y ∼ Y2 . 5. Hence X ∼ Y1 and Y ∼ Y1 ⇒ X ∼ Y . Corollary If α and β are two cardinal numbers such that α ≤ β and β ≤ α, then α = β. Applications of Zorn’s Lemma and the Schroeder–Bernstein Theorem A(i) Let A be a partially ordered set. Then ∃ a totally ordered subset of A which is not a proper subset of any other totally ordered subset of A.

Consequently, ρ is an equivalence relation on N+ × N+ . Remark If the ordered pair (a, b) ∈ N+ × N+ is written as a fraction ab , then the above relation ρ is the usual definition of equality of two fractions: ab = dc ⇔ ad = bc. 2 Partial Order Relations We have made so far little use of reflexive, antisymmetric, and transitive laws. We are familiar with the natural ordering ≤ between two positive integers. This example suggests the abstract concept of a partial order relation, which is a reflexive, antisymmetric, and transitive relation.

10 Let ρ be the binary relation on N+ ×N+ defined by (a, b)ρ(c, d) ⇔ ad = bc. Thus ρ is an equivalence relation. We assume commutative, associative, and cancellative laws for multiplication on N+ . The relation ρ is clearly reflexive and symmetric. Next suppose (a, b)ρ(c, d) and (c, d)ρ(e, f ). Then ad = bc and cf = de ⇒ (ad)(cf ) = (bc)(de) ⇒ af = be ⇒ (a, b)ρ(e, f ) ⇒ ρ is transitive. Consequently, ρ is an equivalence relation on N+ × N+ . Remark If the ordered pair (a, b) ∈ N+ × N+ is written as a fraction ab , then the above relation ρ is the usual definition of equality of two fractions: ab = dc ⇔ ad = bc.

### Basic Modern Algebra with Applications by Mahima Ranjan Adhikari, Avishek Adhikari

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